4sin^2x+4sin(x)+1=0

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Solution for 4sin^2x+4sin(x)+1=0 equation:


Simplifying
4sin2x + 4sin(x) + 1 = 0

Multiply ins * x
4in2sx + 4insx + 1 = 0

Reorder the terms:
1 + 4insx + 4in2sx = 0

Solving
1 + 4insx + 4in2sx = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 4insx + -1 + 4in2sx = 0 + -1

Reorder the terms:
1 + -1 + 4insx + 4in2sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4insx + 4in2sx = 0 + -1
4insx + 4in2sx = 0 + -1

Combine like terms: 0 + -1 = -1
4insx + 4in2sx = -1

Reorder the terms:
1 + 4insx + 4in2sx = -1 + 1

Combine like terms: -1 + 1 = 0
1 + 4insx + 4in2sx = 0

The solution to this equation could not be determined.

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